Equations » Modulus equations
Example 1
| 3x – | 1 | = 8 |
3x – 1 = 8 | of 3x – 1 = –8 |
3x = 9 | of 3x = –7 |
x = 3 | of x = –213 |
Example 2
| 1 – x | 2 | = 8 |
1 – x2 = 8 | of 1 – x2 = –8 |
–x2 = 7 | of –x2 = –9 |
x2 = –7 | of x2 = 9 |
x | = –3 of x = 3 |
(x2 = –7 has no solutions)
How do you get absolute signs in the DWO?
| 3x – 1 | = 8 you key in as abs(3x – 1) = 8.